Don_Dickle@lemmy.world to Ask Science@lemmy.worldEnglish · 10 hours agoIf the sun was dried up or put out and was a rock how much would it weigh?message-squaremessage-square19fedilinkarrow-up115arrow-down15
arrow-up110arrow-down1message-squareIf the sun was dried up or put out and was a rock how much would it weigh?Don_Dickle@lemmy.world to Ask Science@lemmy.worldEnglish · 10 hours agomessage-square19fedilink
minus-squareMuun@lemmy.worldlinkfedilinkEnglisharrow-up9arrow-down1·edit-29 hours agoOkay, very confusing question… So, assuming you want to know how heavy only the “solid at room temperature” elements of the sun are, let’s try this. The sun is 1.989 × 10^30 kilograms. According to this: https://www.thoughtco.com/element-composition-of-sun-607581 we can see the % of total mass for each element. Element % of total atoms % of total mass Hydrogen 91.2 71.0 Helium 8.7 27.1 Oxygen 0.078 0.97 Carbon 0.043 0.40 Nitrogen 0.0088 0.096 Silicon 0.0045 0.099 Magnesium 0.0038 0.076 Neon 0.0035 0.058 Iron 0.030 0.014 Sulfur 0.015 0.040 Doing the math and removing the “gas at room temperature” elements… the total mass would be: 1.7901 * 10^28 kilograms Note: Pretty sure I’ve messed something up here in the calculations but the mass is so ridiculously heavy that I don’t think it really matters.
minus-squareAdmetus@sopuli.xyzlinkfedilinkEnglisharrow-up1·edit-29 hours agoSeems like you answered the question, OP comments at the bottom and thinks it might be picked up by hand in terms of weight.
minus-squarekbal@fedia.iolinkfedilinkarrow-up1·9 hours agoNot many rocks don’t have some oxygen atoms in them, so I chose to include all the astronomical “metals” in my estimate. Interesting to see how little difference it makes.
Okay, very confusing question…
So, assuming you want to know how heavy only the “solid at room temperature” elements of the sun are, let’s try this.
The sun is 1.989 × 10^30 kilograms.
According to this: https://www.thoughtco.com/element-composition-of-sun-607581 we can see the % of total mass for each element.
Doing the math and removing the “gas at room temperature” elements… the total mass would be:
1.7901 * 10^28 kilograms
Note: Pretty sure I’ve messed something up here in the calculations but the mass is so ridiculously heavy that I don’t think it really matters.
Seems like you answered the question, OP comments at the bottom and thinks it might be picked up by hand in terms of weight.
Not many rocks don’t have some oxygen atoms in them, so I chose to include all the astronomical “metals” in my estimate. Interesting to see how little difference it makes.