@el_psd

el_psd@sh.itjust.works · 3 hours ago

Sra. Sheinbaum my people yearn for freedom

el_psd@sh.itjust.works · 3 hours ago

I mean, I place more of the blame for “ending the country” on the fascists and the people who enthusiastically put them into power, but if you want to blame the handful of people who abstained then you do you I guess

el_psd@sh.itjust.works · 18 days ago

I cannot into computers, but draining the capacitors before rebooting has fixed this issue for me in the past. Not sure if this is even possible on your device given you’re running Plasma Mobile

el_psd@sh.itjust.works · 9 months ago

response

Thanks for the catch! Once I noticed that the probability of winning on the initial flip was the difference between the two, I stopped thinking about the other terms…

el_psd@sh.itjust.works · 9 months ago

I read the other answers in the thread, and I definitely would have gotten this wrong without that. This answer stands a chance at least

Independence

A and C are independent, A and B are not. Since you have a chance to win on turn 4 that you do not have on turn 1, P(A|B) = 1/2 + 1/16 + 1/64… = 7/12 != P(A). Conversely, P(A|C) = 1/4 + 1/16 + 1/64… = 1/3 = P(A)